(x^3z^4/y^2)^-3

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Solution for (x^3z^4/y^2)^-3 equation: 


D( x )

(x^3*z^4)/(y^2) = 0

y^2 = 0

(x^3*z^4)/(y^2) = 0

(x^3*z^4)/(y^2) = 0

x^3*y^-2*z^4 = 0 // : y^-2*z^4

x^3 = 0

x = 0

y^2 = 0

y^2 = 0

y^2 = 0

x naleu017Cy do R

x belongs to the empty set

((x^3*z^4)/(y^2))^-3 = 0

x belongs to the empty set

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